mysql>explain select * from film_actor where film_id = 1;
Using index condition:与Using where类似,查询的列不完全被索引覆盖,where条件中是一个前导列的范围;
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mysql> explain select * from film_actor where film_id > 1;
Using temporary:mysql需要创建一张临时表来处理查询。出现这种情况一般是要进行优化的,首先是想到用索引来优化。
1. actor.name没有索引,此时创建了张临时表来distinct mysql> explain select distinct name from actor;
2. film.name建立了idx_name索引,此时查询时extra是using index,没有用临时表 mysql> explain select distinct name from film;
Using filesort:mysql 会对结果使用一个外部索引排序,而不是按索引次序从表里读取行。此时mysql会根据联接类型浏览所有符合条件的记录,并保存排序关键字和行指针,然后排序关键字并按顺序检索行信息。这种情况下一般也是要考虑使用索引来优化的。
1. actor.name未创建索引,会浏览actor整个表,保存排序关键字name和对应的id,然后排序name并检索行记录 mysql> explain select * from actor order by name;
2. film.name建立了idx_name索引,此时查询时extra是using indexmysql> explain select * from film order by name;
索引最佳实践
使用的表
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CREATE TABLE `employees` ( `id` int(11) NOT NULL AUTO_INCREMENT, `name` varchar(24) NOT NULL DEFAULT '' COMMENT '姓名', `age` int(11) NOT NULL DEFAULT '0' COMMENT '年龄', `position` varchar(20) NOT NULL DEFAULT '' COMMENT '职位', `hire_time` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP COMMENT '入职时间', PRIMARY KEY (`id`), KEY `idx_name_age_position` (`name`,`age`,`position`) USING BTREE ) ENGINE=InnoDB AUTO_INCREMENT=4 DEFAULT CHARSET=utf8 COMMENT='员工记录表';
INSERT INTO employees(name,age,position,hire_time) VALUES('LiLei',22,'manager',NOW()); INSERT INTO employees(name,age,position,hire_time) VALUES('HanMeimei', 23,'dev',NOW()); INSERT INTO employees(name,age,position,hire_time) VALUES('Lucy',23,'dev',NOW());
最佳实践
1. 全值匹配
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EXPLAIN SELECT * FROM employees WHERE name= 'LiLei';
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EXPLAIN SELECT * FROM employees WHERE name= 'LiLei' AND age = 22;
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EXPLAIN SELECT * FROM employees WHERE name= 'LiLei' AND age = 22 AND position ='manager';
2.最佳左前缀法则
如果索引了多列,要遵守最左前缀法则。指的是查询从索引的最左前列开始并且不跳过索引中的列。
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EXPLAIN SELECT * FROM employees WHERE age = 22 AND position ='manager'; EXPLAIN SELECT * FROM employees WHERE position = 'manager'; EXPLAIN SELECT * FROM employees WHERE name = 'LiLei';
3.不在索引列上做任何操作(计算、函数、(自动or手动)类型转换),会导致索引失效而转向全表扫描
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EXPLAIN SELECT * FROM employees WHERE name = 'LiLei'; EXPLAIN SELECT * FROM employees WHERE left(name,3) = 'LiLei';
4.存储引擎不能使用索引中范围条件右边的列
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EXPLAIN SELECT * FROM employees WHERE name= 'LiLei' AND age = 22 AND position ='manager'; EXPLAIN SELECT * FROM employees WHERE name= 'LiLei' AND age > 22 AND position ='manager';
5.尽量使用覆盖索引(只访问索引的查询(索引列包含查询列)),减少select *语句
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EXPLAIN SELECT name,age FROM employees WHERE name= 'LiLei' AND age = 23 AND position ='manager';
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EXPLAIN SELECT * FROM employees WHERE name= 'LiLei' AND age = 23 AND position ='manager';
6.mysql在使用不等于(!=或者<>)的时候无法使用索引会导致全表扫描
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EXPLAIN SELECT * FROM employees WHERE name != 'LiLei'
7.is null,is not null 也无法使用索引
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EXPLAIN SELECT * FROM employees WHERE name is null
8.like以通配符开头(’$abc…’)mysql索引失效会变成全表扫描操作
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EXPLAIN SELECT * FROM employees WHERE name like '%Lei'
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EXPLAIN SELECT * FROM employees WHERE name like 'Lei%'
问题:解决like’%字符串%’索引不被使用的方法?
a)使用覆盖索引,查询字段必须是建立覆盖索引字段
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EXPLAIN SELECT name,age,position FROM employees WHERE name like '%Lei%';
b)当覆盖索引指向的字段是varchar(380)及380以上的字段时,覆盖索引会失效!
9.字符串不加单引号索引失效
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EXPLAIN SELECT * FROM employees WHERE name = '1000'; EXPLAIN SELECT * FROM employees WHERE name = 1000;
10.少用or,用它连接时很多情况下索引会失效
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EXPLAIN SELECT * FROM employees WHERE name = 'LiLei' or name = 'HanMeimei';